― Confounded (Confounded), Wednesday, 6 September 2006 14:43 (eighteen years ago)
― Jaimee Stewart (Jaimee), Wednesday, 6 September 2006 20:41 (eighteen years ago)
http://cgm.cs.mcgill.ca/~godfried/walbum/binay.jpg
― Dr. Math, Thursday, 28 September 2006 06:27 (eighteen years ago)
― Confounded (Confounded), Thursday, 28 September 2006 16:26 (eighteen years ago)
http://www.taymouthtwplibrary.org/images/student_happy_with_test_score_hg_clr.gif
― velko, Tuesday, 5 January 2010 21:53 (fifteen years ago)
How do I find the mean expected result of a function over a known range? Like, say I have f(x) = x^2 or something, what's the expected value for 0 < x < 1 ? Is this an integration thing?
― Gravel Puzzleworth, Tuesday, 5 January 2010 22:32 (fifteen years ago)
you should've asked me that in 2005. I could've told you.
― un(!)registered (unregistered), Tuesday, 5 January 2010 22:52 (fifteen years ago)
integrate the function from 0 to 1 ---> the integral is x^3/3 so 1/3 - 0/3 = 1/3divide by (1-0) average is 1/3
amirite?
― jortin shartgent (harbl), Tuesday, 5 January 2010 23:19 (fifteen years ago)
wikipedia says iamritehttp://upload.wikimedia.org/math/9/2/c/92cdaca353a4fc0f69572d7770fbe734.png
― jortin shartgent (harbl), Tuesday, 5 January 2010 23:22 (fifteen years ago)
juris doctor of math
― velko, Tuesday, 5 January 2010 23:26 (fifteen years ago)
bachelor of math ; )
― jortin shartgent (harbl), Tuesday, 5 January 2010 23:28 (fifteen years ago)
where was that attempt at advmaths integration that devolved into a robot versus dinosaur epic battle mid-page posted? pretty sure it was on ilx right?
― ┌∩┐(◕_◕)┌∩┐ (Steve Shasta), Tuesday, 5 January 2010 23:42 (fifteen years ago)